final update on 4121
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@@ -22,7 +22,23 @@ $$
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However, the quarter cantor set removes $\frac{3^{n-1}}{4^n}$ of the total "content", and the total length removed after infinitely many steps is:
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_skip this part, some error occurred._
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Every time we remove $\frac{1}{4^n}$ of the remaining intervals. So on each layer, we remove $\frac{2^{n-1}}{4^n}$ of the total "content".
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So the total length removed is:
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$$
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\begin{aligned}
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1-\frac{1}{4}-\frac{2}{4^2}-\frac{2^2}{4^3}-\cdots&=1-\frac{1}{4}\sum_{n=0}^{\infty} \left(\frac{2}{4}\right)^n\\
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&=1-\frac{1}{4}\cdot\frac{1}{1-\frac{2}{4}}\\
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&=1-\frac{1}{4}\cdot\frac{4}{2}\\
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&=1-\frac{1}{2}\\
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&=\frac{1}{2}
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\end{aligned}
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$$
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#### Generalized Cantor set (SVC(n))
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The outer content of $SVC(n)$ is $\frac{n-3}{n-2}$.
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#### Monotonicity of outer content
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