update notations and fix typos
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@@ -296,7 +296,7 @@ If $c'\geq 8c$, then $T(n)\leq c'n\log n+1$.
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$E[T(n)]\leq c'n\log n+1=O(n\log n)$
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EOP
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QED
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A more elegant proof:
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@@ -345,5 +345,5 @@ E[X]&=\sum_{i=0}^{n-2}\sum_{j=i+1}^{n-1}\frac{2}{j-i+1}\\
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$$
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EOP
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QED
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