diff --git a/content/Math4202/Math4202_L18.md b/content/Math4202/Math4202_L18.md new file mode 100644 index 0000000..fbea80b --- /dev/null +++ b/content/Math4202/Math4202_L18.md @@ -0,0 +1,3 @@ +# Math4202 Topology II (Lecture 18) + +Revisit the idea of proof from previous lecture, using brick construction for lifting maps. diff --git a/content/Math4302/Math4302_L16.md b/content/Math4302/Math4302_L16.md new file mode 100644 index 0000000..dea9210 --- /dev/null +++ b/content/Math4302/Math4302_L16.md @@ -0,0 +1,94 @@ +# Math4302 Modern Algebra (Lecture 16) + +## Group + +### Normal subgroup + +Suppose $H\leq G$, then the following are equivalent: + +1. $aH=Ha$ for all $a\in G$ +2. $aHa^{-1}= H$ for all $a\in G$ +3. $aha^{-1}\subseteq H$ for all $a\in G$ +4. the operation $(aH)(bH)=abH$ is well defined for all $a,b\in G$, on the set of left coset of $H\leq G$ + +Then $H\trianglelefteq G$ + +If $H\trianglelefteq G$, then the set of left coset of $H\leq G$ is a group under the operation $(aH)(bH)=abH$ + +$G/H$ is factor (or quotient) group of $G$ by $H$ + +identity $H$=$eH$ + +
+Example + +If $|H|=\frac{1}{2}|G|$, then $H$ is a normal subgroup of $G$, then $G/H$ is isomorphic to $\mathbb{Z}_2$ + +--- + +Let $\phi:G\to G'$ be a homomorphism, then $\ker(\phi)\trianglelefteq G$ + +$\mathbb{Z}/5\mathbb{Z}\trianglelefteq \mathbb{Z}$ + +And $\mathbb{Z}/5\mathbb{Z}$ is isomorphic to $\mathbb{Z}_5$ + +--- + +$G/G$ is isomorphic to trivial group + +--- + +$G/\{e\}$ is isomorphic to $G$ + +--- + +$\mathbb{R}/\mathbb{Z}$ is isomorphic to $S^1$ + +--- + +$\mathbb{Z}_3\times\mathbb{Z}_6/\langle (1,1)\rangle$ is isomorphic to $\mathbb{Z}_3$ + +$\langle (1,1)\rangle=\{(1,1),(2,2),(0,3),(1,4),(2,5),(0,0)\}$ + +
+ +Recall + +1. The lagrange theorem, if $G$ is finite and $H\leq G$, then $|H| | |G|$. +2. If $G$ is finite, abelian, $d||G|$, then $G$ has a subgroup of order $d$. + +We will show that 2. is not true if $G$ is not abelian. (consider $A_4$ with order 12, have no subgroup of order 6) + +
+Proof + +Suppose $H\leq A_4$, and $|H|=6$. Then $A_4/H$ is normal in $A_4$, (since $|A_4/H|=2$), and $A_4/H$ is isomorphic to $\mathbb{Z}_2$. + +In other words, every element in $A_4/H$ has either order 1 or 2. + +So for any $\sigma\in A_4$, $(\sigma H)(\sigma H)=\sigma^2 H$. Therefore $\sigma^2=H$. + +But $\sigma=(1,3)(1,2)\in A_4$ and $\sigma^2=(1,3,2)\in H$. + +Similarly, $(1,3,2)(1,2,4)\dots(1,4,3)$ are all even permutations, making $|H|\geq 8$, that is a contradiction. + +
+ +#### Fundamental homomorphism theorem (first isomorphism theorem) + +If $\phi:G\to G'$ is a homomorphism, then the function $f:G/\ker(\phi)\to \phi(G)$, ($\phi(G)\subseteq G'$) given by $f(a\ker(\phi))=\phi(a)$, $\forall a\in G$, is an well-defined isomorphism. + +
+Proof + +First we will prove the well definedness and injectivity of $f$. + +We need to check the map will not map the same coset represented in different ways to different elements. + +Suppose $a\ker(\phi)=a'\ker(\phi)$, then $a^{-1}b\in \ker(\phi)$, this implies $\phi(a^{-1}b)=e'$ so $\phi(a)=\phi(b)$. + +Reverse the direction to prove the converse. + +Other properties are trivial. + +
diff --git a/content/Math4302/Math4302_L17.md b/content/Math4302/Math4302_L17.md new file mode 100644 index 0000000..dd348b8 --- /dev/null +++ b/content/Math4302/Math4302_L17.md @@ -0,0 +1,3 @@ +# Math4302 Modern Algebra (Lecture 17) + +## Subgroup \ No newline at end of file diff --git a/content/Math4302/_meta.js b/content/Math4302/_meta.js index d943f54..c5cc85d 100644 --- a/content/Math4302/_meta.js +++ b/content/Math4302/_meta.js @@ -18,4 +18,6 @@ export default { Math4302_L13: "Modern Algebra (Lecture 13)", Math4302_L14: "Modern Algebra (Lecture 14)", Math4302_L15: "Modern Algebra (Lecture 15)", + Math4302_L16: "Modern Algebra (Lecture 16)", + Math4302_L17: "Modern Algebra (Lecture 17)", }