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@@ -8,9 +8,9 @@ The $*$ operation has the following properties:
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#### Properties for the path product operation
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Let $[f],[g]\in \Pi_1(X)$, for $[f]\in \Pi_1(X)$, let $s:\Pi_1(X)\to X, [f]\mapsto f(0)$ and $t:\Pi_1(X)\to X, [f]\mapsto f(1)$.
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Let $[f],[g]\in pi_1(X)$, for $[f]\in pi_1(X)$, let $s:pi_1(X)\to X, [f]\mapsto f(0)$ and $t:pi_1(X)\to X, [f]\mapsto f(1)$.
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Note that $t([f])=s([g])$, $[f]*[g]=[f*g]\in \Pi_1(X)$.
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Note that $t([f])=s([g])$, $[f]*[g]=[f*g]\in pi_1(X)$.
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This also satisfies the associativity. $([f]*[g])*[h]=[f]*([g]*[h])$.
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@@ -51,33 +51,33 @@ Let $x_0\in X$. A path starting and ending at $x_0$ is called a loop based at $x
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The fundamental group of $X$ at $x$ is defined to be
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$$
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(\Pi_1(X,x),*)
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(pi_1(X,x),*)
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$$
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where $*$ is the product operation, and $\Pi_1(X,x)$ is the set o homotopy classes of loops in $X$ based at $x$.
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where $*$ is the product operation, and $pi_1(X,x)$ is the set o homotopy classes of loops in $X$ based at $x$.
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<details>
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<summary>Example of fundamental group</summary>
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Consider $X=[0,1]$, with subspace topology from standard topology in $\mathbb{R}$.
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$\Pi_1(X,0)=\{e\}$, (constant function at $0$) since we can build homotopy for all loops based at $0$ as follows $H(s,t)=(1-t)f(s)+t$.
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$pi_1(X,0)=\{e\}$, (constant function at $0$) since we can build homotopy for all loops based at $0$ as follows $H(s,t)=(1-t)f(s)+t$.
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And $\Pi_1(X,1)=\{e\}$, (constant function at $1$.)
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And $pi_1(X,1)=\{e\}$, (constant function at $1$.)
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---
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Let $X=\{1,2\}$ with discrete topology.
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$\Pi_1(X,1)=\{e\}$, (constant function at $1$.)
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$pi_1(X,1)=\{e\}$, (constant function at $1$.)
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$\Pi_1(X,2)=\{e\}$, (constant function at $2$.)
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$pi_1(X,2)=\{e\}$, (constant function at $2$.)
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---
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Let $X=S^1$ be the circle.
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$\Pi_1(X,1)=\mathbb{Z}$ (related to winding numbers, prove next week).
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$pi_1(X,1)=\mathbb{Z}$ (related to winding numbers, prove next week).
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</details>
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@@ -85,7 +85,7 @@ A natural question is, will the fundamental group depends on the base point $x$?
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#### Definition for $\hat{\alpha}$
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Let $\alpha$ be a path in $X$ from $x_0$ to $x_1$. $\alpha:[0,1]\to X$ such that $\alpha(0)=x_0$ and $\alpha(1)=x_1$. Define $\hat{\alpha}:\Pi_1(X,x_0)\to \Pi_1(X,x_1)$ as follows:
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Let $\alpha$ be a path in $X$ from $x_0$ to $x_1$. $\alpha:[0,1]\to X$ such that $\alpha(0)=x_0$ and $\alpha(1)=x_1$. Define $\hat{\alpha}:pi_1(X,x_0)\to pi_1(X,x_1)$ as follows:
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$$
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\hat{\alpha}(\beta)=[\bar{\alpha}]*[f]*[\alpha]
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@@ -93,12 +93,12 @@ $$
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#### $\hat{\alpha}$ is a group homomorphism
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$\hat{\alpha}$ is a group homomorphism between $(\Pi_1(X,x_0),*)$ and $(\Pi_1(X,x_1),*)$
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$\hat{\alpha}$ is a group homomorphism between $(pi_1(X,x_0),*)$ and $(pi_1(X,x_1),*)$
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<details>
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<summary>Proof</summary>
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Let $f,g\in \Pi_1(X,x_0)$, then $\hat{\alpha}(f*g)=\hat{\alpha}(f)\hat{\alpha}(g)$
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Let $f,g\in pi_1(X,x_0)$, then $\hat{\alpha}(f*g)=\hat{\alpha}(f)\hat{\alpha}(g)$
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$$
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\begin{aligned}
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@@ -129,4 +129,4 @@ The other case is the same
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#### Corollary of fundamental group
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If $X$ is path-connected and $x_0,x_1\in X$, then $\Pi_1(X,x_0)$ is isomorphic to $\Pi_1(X,x_1)$.
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If $X$ is path-connected and $x_0,x_1\in X$, then $pi_1(X,x_0)$ is isomorphic to $pi_1(X,x_1)$.
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