Update CSE5313_L14.md
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@@ -295,3 +295,7 @@ $\Psi_D$ invertible by construction.
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- DC computes $\Psi_D^{-1}C_DM = (S+\Psi_D^{-1}\Delta_D^T, T)$
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- DC computes $\Psi_D^{-1}C_DM = (S+\Psi_D^{-1}\Delta_D^T, T)$
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- DC obtains $T$.
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- DC obtains $T$.
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- Subtracts $\Psi_D^{-1}\Delta_D T^T$ from $S+\Psi_D^{-1}\Delta_D T^T$ to obtain $S$.
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- Subtracts $\Psi_D^{-1}\Delta_D T^T$ from $S+\Psi_D^{-1}\Delta_D T^T$ to obtain $S$.
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<details>
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<summary>Fill an example here please.</summary>
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</details>
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