From 73bd3d6a586960dc48ec5376fb2205a85e57fe26 Mon Sep 17 00:00:00 2001
From: Zheyuan Wu <60459821+Trance-0@users.noreply.github.com>
Date: Sun, 8 Dec 2024 14:51:58 -0600
Subject: [PATCH] rename error files

---
 pages/CSE442T/Exam_reviews/{CSE441T_E2.md => CSE442T_E2.md} | 0
 pages/Math429/Math429_L13.md                                | 2 --
 2 files changed, 2 deletions(-)
 rename pages/CSE442T/Exam_reviews/{CSE441T_E2.md => CSE442T_E2.md} (100%)

diff --git a/pages/CSE442T/Exam_reviews/CSE441T_E2.md b/pages/CSE442T/Exam_reviews/CSE442T_E2.md
similarity index 100%
rename from pages/CSE442T/Exam_reviews/CSE441T_E2.md
rename to pages/CSE442T/Exam_reviews/CSE442T_E2.md
diff --git a/pages/Math429/Math429_L13.md b/pages/Math429/Math429_L13.md
index 6923b3e..d2d94ea 100644
--- a/pages/Math429/Math429_L13.md
+++ b/pages/Math429/Math429_L13.md
@@ -26,8 +26,6 @@ Suppose $T$ is injective, then $null\ T={0}$, i.e $dim(null\ T)=0$, since $dim\
 
 If $T$ is surjective, then $dim\ range\ T=dim\ W$ but then $dim\ V=dim\ null\ T+dim\ W\implies dim\ null\ T=0$, so $T$ is injective, $T\ surjective\implies T\ injective$.
 
-$% you cannot see this line....$
-
 #### Theorem 3.68
 
 Suppose $V,W$ finite dimensional $dim\ V=dim\ W$, then for $T\in\mathscr{L}(V,W)$ and $S\in \mathscr{L}(W,V)$, then $ST=I\implies TS=I$