proof format updates using gfm
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@@ -88,7 +88,8 @@ $$
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is a strong one-way function.
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Proof:
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<details>
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<summary>Proof</summary>
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1. Since $\exist P.P.T.$ that computes $f(x),\forall x$ we use this $q(n)$ polynomial times to compute $g$.
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2. (Idea) $a$ has to succeed in inverting $f$ all $q(n)$ times.
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@@ -98,7 +99,7 @@ Proof:
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Then $P[a$ inverting $g]\sim P[a$ inverts $f$ all $q(n)]$ times. $<(1-\frac{1}{p(n)})^{q(n)}=(1-\frac{1}{p(n)})^{np(n)}<(e^{-\frac{1}{p(n)}})^{np(n)}=e^{-n}$ which is negligible function.
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QED
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</details>
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_we can always force the adversary to invert the weak one-way function for polynomial time to reach the property of strong one-way function_
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