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2026-01-12 12:55:04 -06:00
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@@ -635,6 +635,7 @@ A topological space $(X,\mathcal{T})$ is normal if for any disjoint closed sets
Some corollaries:
1. $X$ is normal if and only if given a closed set $A\subseteq X$, there is open neighborhood $V$ of $A$ such that $\overline{V}\subseteq U$.
2. Every compact Hausdorff spaces is normal.
> [!CAUTION]
>
@@ -646,4 +647,12 @@ Let $X$ be a regular space with countable basis, then $X$ is normal.
*Prove by taking disjoint open neighborhoods by countable cover.*
### Urysohn Lemma
Let $X$ be a normal space, $A,B$ be two closed disjoint set in $X$, then there exists continuous function: $f:X\to[0,1]$ such that $f(A)=\{0\}$ and $f(B)=\{1\}$.
#### Urysohn metrization theorem
If $X$ is normal (regular and second countable) topological space, then $X$ is metrizable.