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Zheyuan Wu
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# CSE4303 Introduction to Computer Security (Lecture 15)
## Cryptography applications
### Authentication (...of users, not data)
- Traditional authentication: password-based, single-factor
- Disadvantage: convenience often chosen over security
- Weak passwords
- Password re-use: one password compromised ==> many accounts compromised
- Attack: "credential stuffing" (testing single stolen password against many accounts)
#### SSH keys
- Idea: relieve burden of secure passwords
- Use public/private-key auth instead (can be automated!)
- Use secure password once to exchange public key
- Protocol: challenge/response to verify possession of keys
#### Case Study: SSH
- SSH can use public-key based authentication to authenticate users
- Generate a pair of public and private keys: `ssh-keygen -t rsa`
- private key: `/home/seed/.ssh/id_rsa`
- public key: `/home/seed/.ssh/id_rsa.pub`
- Register public key with server:
- Send the public key file to the remote server using a secure channel
- Add public key to the authorization file `~/.ssh/authorized_keys`
- Server can use key to authenticate clients
#### Time-based One-Time Password (TOTP)
- Goal: provide secure 2nd factor for authentication
- Idea:
- Generate one-time (single-use) password for each login attempt
- Compute one-time password using secure HMAC with current time as a parameter
- Key used for HMAC: exchanged once at setup
- Protocol: open standard published by OATH, IETF
- HMAC-based One-Time Password (HOTP)
- e.g. $TOTP(k) = HOTP(k, C_t)$, where $C_t$ is absolute measure of current time interval
- Num digits taken from output: 6 to 10
### Ransomware
- Idea: attacker encrypts victim's data with symmetric cipher, requires ransom payment to decrypt (or provide key)
- System model: any data store (company database, municipal database, user's hard drive, etc.)
- Threat model: attacker who has already compromised victim's system
- Vuln: lack of backups (or prohibitive time to restore); whatever vuln allowed attacker into system
- Surface: exposed data, and surface of original compromise
- Vector: encrypt data store and erase or replace original data store
- Mitigation/defense: keep up-to-date backups (possibly "air-gapped") in separate location; practice restoring from backups
- Enabler: anonymity of Bitcoin payments
- Recent-ish examples:
- Baltimore 2019 (didn't pay, est. $18 million to fix)
- Atlanta 2018 (~$9 million to fix)
- Lake City & Riviera City, Florida 2019 (did pay, $500,000+ apiece)
- Many others since these
- One of the top projected trends in cybersecurity in 2021 (e.g. by CSO online)
### Post-Quantum (PQ) crypto
- Fundamentally different computation paradigm than "classical" von Neumann or dataflow models
- Relies on properties of quantum physics to solve problems efficiently
- Superposition: state of quantum bit ("qubit") expressed by probability model over continuous range of values (vs. classic bit: 0 or 1 only)
- Like being able to operate on all possible bit combos of a register simultaneously, instead of operating on only one among all possibilities
- Entanglement: operating on one qubit affects others
### Zero-Knowledge (ZK) proofs
### Homomorphic encryption

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# CSE4303 Introduction to Computer Security (Lecture 16)
## System security
- Why system security / platform security?
- All code runs on some physical machine!
- The cloud is not a cloud
- Web pages are just data and code copied from a server that also manages the transfer
- Why Linux?
- Majority of web servers run Linux (esp. Cloud); popular in embedded, mobile devices
### Operating system background
Context: computing stack
| Layer | Description |
| --- | --- |
| Application | Web browser, user apps, DNS |
| OS:libs | Memory allocations, compiler/linker|
| OS:kernel | Process control, networking, file system, access control|
| OS:drivers | Manage hardware|
| (Firmware) | Minimal hardware management (if no full OS)|
|Hardware | Processor, cahce, RAM, disk, USB ports|
#### Operating systems
- Operating System:
- Provides easier to use and high level **abstractions** for resources such as address space for memory and files for disk blocks.
- Provides **controlled access** to hardware resources.
- Provides **isolation** between different processes and between the processes running untrusted/application code and the trusted operating system.
- Need for trusting an operating system
- Why do we need to trust the operating system? (AKA a Trusted Computing Base or TCB)
- What requirements must it meet to be trusted?
- TCB Requirements:
- 1. Tamper-proof
- 2. Complete mediation (reference monitor)
- 3. Correct
Isolating OS from Untrusted User Code
- How do we meet the first requirement of a TCB (e.g., isolation or tamper-proofness)?
- Hardware support for memory protection
- Processor execution modes (system AND user modes, execution rings)
- Privileged instructions which can only be executed in system mode
- System calls used to transfer control between user and system code
System Calls: Going from User to OS Code
- System calls used to transfer control between user and system code
- Such calls come through "call gates" and return back to user code.
- The processor execution mode or privilege ring changes when call and return happen.
- x86 `sysenter` / `sysexit` instructions
Isolating User Processes from Each Other
- How do we meet the user/user isolation and separation?
- OS uses hardware support for memory protection to ensure this.
Virtualization
- OS is large and complex, even different operating systems may be desired by different customers
- Compromise of an OS impacts all applications
Complete Mediation: The TCB
- Make sure that no protected resource (e.g., memory page or file) could be accessed without going through the TCB
- TCB acts as a reference monitor that cannot be bypassed
- Privileged instructions
Limiting the Damage oa a Hacked OS
Use: Hypervisor, virtual machines, guest OS and applications
Compromise of OS in VM1 only impacts applications running on VM1
### Secure boot and Root of Trust (RoT)
Goal: create chain of trust back to hardware-stored cryptographic keys
#### Secure enclave: overview (Intel SGX)
![Intel SGX](https://notenextra.com/CSE4303/Intel_SGX.png)
Goal: keep sensitive data within hardware-isolated encrypted environment
### Access control
Controlling Accesses to Resources
- TCB (reference monitor) sees a request for a resource, how does it decide whether it should be granted?
- Example: Should John's process making a request to read a certain file be allowed to do so?
- Authentication establishes the source of a request (e.g., John's UID)
- Authorization (or access control) answers the question if a certain source of a request (User ID) is allowed to read the file
- Subject who owns a resource (creates it) should be able to control access to it (sometimes this is not true)
- Access control
- Basically, it is about who is allowed to access what.
- Two parts
- Part I - Policy: decide who should have access to certain resources (access control policy)
- Part II - Enforcement: only accesses defined by the access control policy are granted.
- Complete mediation is essential for successful enforcement
Discretionary Access Control
- In discretionary access control (DAC), owner of a resource decides how it can be shared
- Owner can choose to give read or write access to other users
- Two problems with DAC:
- You cannot control if someone you share a file with will not further share the data contained in it
- Cannot control "information flow"
- In many organizations, a user does not get to decide how certain type of data can be shared
- Typically the employer may mandate how to share various types of sensitive data
- Mandatory Access Control (MAC) helps address these problems
Mandatory Access Control (MAC) Models
- User works in a company and the company decides how data should be shared
- Hospital owns patient records and limits their sharing
- Regulatory requirements may limit sharing
- HIPAA for health information
#### Example: Linux system controls
Unix file access control list
- Each file has owner and group
- Permissions set by owner
- Read, write, execute
- Owner, group, other
- Represented by vector of four octal values
- Only owner, root can change permissions
- This privilege cannot be delegated or shared
- Setid bits -- Discuss in a few slides
Process effective user id (EUID)
- Each process has three IDs (+ more under Linux)
- Real user ID (RUID)
- Same as the user ID of parent (unless changed)
- Used to determine which user started the process
- Effective user ID (EUID)
- From set user ID bit on the file being executed, or sys call
- Determines the permissions for process
- File access and port binding
- Saved user ID (SUID)
- So previous EUID can be restored
- Real group ID, effective group ID used similarly
#### Weaknesses in Unix isolation, privileges
- Shared resources
- Since any process can create files in `/tmp` directory, an untrusted process may create files that are used by arbitrary system processes
- Time-of-Check-to-Time-of-Use (TOCTTOU), i.e. race conditions
- Typically, a root process uses system call to determine if initiating user has permission to a particular file, e.g. `/tmp/X`.
- After access is authorized and before the file open, user may change the file `/tmp/X` to a symbolic link to a target file `/etc/shadow`.
### Hazard: race conditions

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@@ -19,4 +19,6 @@ export default {
CSE4303_L12: "Introduction to Computer Security (Lecture 12)",
CSE4303_L13: "Introduction to Computer Security (Lecture 13)",
CSE4303_L14: "Introduction to Computer Security (Lecture 14)",
CSE4303_L15: "Introduction to Computer Security (Lecture 15)",
CSE4303_L16: "Introduction to Computer Security (Lecture 16)"
}

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@@ -29,6 +29,8 @@ $f|_{B^2}$ is a continuous map from $B^2\to \mathbb{R}^2-\{0\}$.
$f|_{S^1=\partial B^2}:S^1\to \mathbb{R}-\{0\}$ **is nulhomotopic**.
> Recall that: Any map $g:S^1\to Y$ is nulhomotopic whenever it extends to a continuous map $G:B^2\to Y$.
Construct a homotopy between $f|_{S^1}$ and $g$
$$
@@ -57,10 +59,9 @@ Therefore $f$ must have a root in $B^2$.
<details>
<summary>Proof: part 2</summary>
If \|a_{n-1}\|+\|a_{n-2}\|+\cdots+\|a_0\|< R$ has a root in the disk $B^2_R$. (and $R\geq 1$, otherwise follows part 1)
Consider $\tilde{f}(x)=f(Rx)$.
If $\|a_{n-1}\|+\|a_{n-2}\|+\cdots+\|a_0\|< R$ has a root in the disk $B^2_R$. (and $R\geq 1$, otherwise follows part 1)
Consider $\tilde{f}(x)=f(Rx)$.
$$
\begin{aligned}
\tilde{f}(x)
@@ -71,7 +72,7 @@ $$
$$
\begin{aligned}
\|\frac{a_{n-1}}{R}\|+\|\frac{a_{n-2}}{R^2}\|+\cdots+\|\frac{a_0}{R^n}\|&=\frac{1}{R}\|a_{n-1}\|+\frac{1}{R^2}\|a_{n-2}\|+\cdots+\frac{1}{R^n}\|a_0\|\\
\left\|\frac{a_{n-1}}{R}\right\|+\left\|\frac{a_{n-2}}{R^2}\right\|+\cdots+\left\|\frac{a_0}{R^n}\right\|&=\frac{1}{R}\|a_{n-1}\|+\frac{1}{R^2}\|a_{n-2}\|+\cdots+\frac{1}{R^n}\|a_0\|\\
&<\frac{1}{R}\left(\|a_{n-1}\|+\|a_{n-2}\|+\cdots+\|a_0\|\right)\\
&<\frac{1}{R}<1
\end{aligned}