From e57c53b10d23e58c0ea0ed4055243b7b7f6af5bb Mon Sep 17 00:00:00 2001 From: Trance-0 <60459821+Trance-0@users.noreply.github.com> Date: Fri, 25 Jul 2025 10:22:07 -0500 Subject: [PATCH] update tokens --- app/layout.tsx | 4 ++-- components/docsearch.tsx | 6 +++--- content/Math401/Math401_T6.md | 2 +- 3 files changed, 6 insertions(+), 6 deletions(-) diff --git a/app/layout.tsx b/app/layout.tsx index 252442f..6f56dd0 100644 --- a/app/layout.tsx +++ b/app/layout.tsx @@ -62,7 +62,7 @@ export default async function RootLayout({ children }) { dark: 59, light: 35 } - }} /> + }}/> } + search={} > {children} {/* SpeedInsights in vercel */} diff --git a/components/docsearch.tsx b/components/docsearch.tsx index ae95a40..668281c 100644 --- a/components/docsearch.tsx +++ b/components/docsearch.tsx @@ -8,9 +8,9 @@ import '@docsearch/css'; function AlgoliaSearch() { return ( ); } diff --git a/content/Math401/Math401_T6.md b/content/Math401/Math401_T6.md index 5a4f781..196b067 100644 --- a/content/Math401/Math401_T6.md +++ b/content/Math401/Math401_T6.md @@ -76,7 +76,7 @@ This is a contradiction, so $|\psi^+\rangle$ is entangled. #### Density operator -A density operator is a Hermitian, positive semi-definite operator with trace 1. +A density operator is a [Hermitian](https://notenextra.trance-0.com/Math401/Math401_T5#definition-of-hermitian-operator), positive semi-definite operator with trace 1. The density operator of a pure state $|\psi\rangle$ is $\rho=|\psi\rangle\langle\psi|$.