From e57c53b10d23e58c0ea0ed4055243b7b7f6af5bb Mon Sep 17 00:00:00 2001
From: Trance-0 <60459821+Trance-0@users.noreply.github.com>
Date: Fri, 25 Jul 2025 10:22:07 -0500
Subject: [PATCH] update tokens
---
app/layout.tsx | 4 ++--
components/docsearch.tsx | 6 +++---
content/Math401/Math401_T6.md | 2 +-
3 files changed, 6 insertions(+), 6 deletions(-)
diff --git a/app/layout.tsx b/app/layout.tsx
index 252442f..6f56dd0 100644
--- a/app/layout.tsx
+++ b/app/layout.tsx
@@ -62,7 +62,7 @@ export default async function RootLayout({ children }) {
dark: 59,
light: 35
}
- }} />
+ }}/>
}
+ search={}
>
{children}
{/* SpeedInsights in vercel */}
diff --git a/components/docsearch.tsx b/components/docsearch.tsx
index ae95a40..668281c 100644
--- a/components/docsearch.tsx
+++ b/components/docsearch.tsx
@@ -8,9 +8,9 @@ import '@docsearch/css';
function AlgoliaSearch() {
return (
);
}
diff --git a/content/Math401/Math401_T6.md b/content/Math401/Math401_T6.md
index 5a4f781..196b067 100644
--- a/content/Math401/Math401_T6.md
+++ b/content/Math401/Math401_T6.md
@@ -76,7 +76,7 @@ This is a contradiction, so $|\psi^+\rangle$ is entangled.
#### Density operator
-A density operator is a Hermitian, positive semi-definite operator with trace 1.
+A density operator is a [Hermitian](https://notenextra.trance-0.com/Math401/Math401_T5#definition-of-hermitian-operator), positive semi-definite operator with trace 1.
The density operator of a pure state $|\psi\rangle$ is $\rho=|\psi\rangle\langle\psi|$.