update build and types
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@@ -166,11 +166,11 @@ y \\
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\end{pmatrix}
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$$
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Constraint from a match $(x_i,x_i^′)$: $x_i^′≅Hx_i$
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Constraint from a match $(x_i,x_i^')$: $x_i^'≅Hx_i$
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How can we get rid of the scale ambiguity?
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Cross product trick: $x_i^′ × Hx_i=0$
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Cross product trick: $x_i^' × Hx_i=0$
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The cross product is defined as:
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@@ -181,9 +181,9 @@ $$
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Let $h_1^T, h_2^T, h_3^T$ be the rows of $H$. Then
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$$
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x_i^′ × Hx_i=\begin{pmatrix}
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x_i^′ \\
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y_i^′ \\
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x_i^' × Hx_i=\begin{pmatrix}
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x_i^' \\
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y_i^' \\
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1
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\end{pmatrix} \times \begin{pmatrix}
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h_1^T x_i \\
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@@ -192,18 +192,18 @@ x_i^′ × Hx_i=\begin{pmatrix}
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\end{pmatrix}
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=
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\begin{pmatrix}
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y_i^′ h_3^T x_i−h_2^T x_i \\
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h_1^T x_i−x_i^′ h_3^T x_i \\
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x_i^′ h_2^T x_i−y_i^′ h_1^T x_i
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y_i^' h_3^T x_i−h_2^T x_i \\
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h_1^T x_i−x_i^' h_3^T x_i \\
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x_i^' h_2^T x_i−y_i^' h_1^T x_i
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\end{pmatrix}
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$$
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Constraint from a match $(x_i,x_i^′)$:
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Constraint from a match $(x_i,x_i^')$:
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$$
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x_i^′ × Hx_i=\begin{pmatrix}
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x_i^′ \\
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y_i^′ \\
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x_i^' × Hx_i=\begin{pmatrix}
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x_i^' \\
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y_i^' \\
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1
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\end{pmatrix} \times \begin{pmatrix}
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h_1^T x_i \\
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@@ -212,9 +212,9 @@ x_i^′ × Hx_i=\begin{pmatrix}
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\end{pmatrix}
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=
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\begin{pmatrix}
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y_i^′ h_3^T x_i−h_2^T x_i \\
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h_1^T x_i−x_i^′ h_3^T x_i \\
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x_i^′ h_2^T x_i−y_i^′ h_1^T x_i
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y_i^' h_3^T x_i−h_2^T x_i \\
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h_1^T x_i−x_i^' h_3^T x_i \\
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x_i^' h_2^T x_i−y_i^' h_1^T x_i
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\end{pmatrix}
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$$
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@@ -222,9 +222,9 @@ Rearranging the terms:
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$$
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\begin{bmatrix}
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0^T &-x_i^T &y_i^′ x_i^T \\
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x_i^T &0^T &-x_i^′ x_i^T \\
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y_i^′ x_i^T &x_i^′ x_i^T &0^T
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0^T &-x_i^T &y_i^' x_i^T \\
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x_i^T &0^T &-x_i^' x_i^T \\
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y_i^' x_i^T &x_i^' x_i^T &0^T
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\end{bmatrix}
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\begin{bmatrix}
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h_1 \\
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