Update Math4121_L25.md

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Zheyuan Wu
2025-03-21 11:05:28 -05:00
parent 502e24c30d
commit da7b8f58a6

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@@ -60,6 +60,18 @@ Since $m[q_j,q_j]=0$, $m(S)=0$.
Since $c_e(SVC(4))=\frac{1}{2}$ and $c_i(SVC(4))=0$, it is not Jordan measurable.
$S$ is Borel measurable with $m(S)=\frac{1}{2}$. (use setminus and union to show)
#### Proposition 5.3
Let $\mathcal{B}$ be the Borel sets in $\mathbb{R}$. Then the cardinality of $\mathcal{B}$ is $2^{\aleph_0}=\mathfrak{c}$. But the cardinality of the set of Jordan measurable sets is $2^{\mathfrak{c}}$.
Sketch of proof:
SVC(3) is Jordan measurable, but $|SVC(3)|=\mathfrak{c}$. so $|\mathscr{P}(SVC(3))|=2^\mathfrak{c}$.
But for any $S\subset \mathscr{P}(SVC(3))$, $c_e(S)\leq c_e(SVC(3))=0$ so $S$ is Jordan measurable.
However, there are $\mathfrak{c}$ many intervals and $\mathcal{B}$ is generated by countable operations from intervals.