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2025-07-25 10:22:07 -05:00
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content/Math401/Math401_T6.md
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@@ -76,7 +76,7 @@ This is a contradiction, so $|\psi^+\rangle$ is entangled.
#### Density operator
A density operator is a Hermitian, positive semi-definite operator with trace 1.
A density operator is a [Hermitian](https://notenextra.trance-0.com/Math401/Math401_T5#definition-of-hermitian-operator), positive semi-definite operator with trace 1.
The density operator of a pure state $|\psi\rangle$ is $\rho=|\psi\rangle\langle\psi|$.