2.1 KiB
Math4302 Modern Algebra (Lecture 18)
Groups
Factor group
Suppose G is a group, and H\trianglelefteq G, then G/H is a group.
Recall from last lecture, if \phi:G\to G' is a homomorphism, then G/\ker(\phi)\simeq \phi(G)\leq G'.
Example (continue from last lecture)
\mathbb{Z}\times\mathbb{Z}/\langle (1,1)\rangle\simeq \mathbb{Z}
Take \phi(a,b)=a-b, this is a surjective homomorphism from \mathbb{Z}\times\mathbb{Z}/\langle (1,1)\rangle to \mathbb{Z}
\mathbb{Z}\times\mathbb{Z}/\langle (2,1)\rangle\simeq \mathbb{Z}
where \langle (2,1)\rangle=\{(2b,b)|b\in \mathbb{Z}\}
Take \phi(a,b)=a-2b, this is a surjective homomorphism from \mathbb{Z}\times\mathbb{Z}/\langle (2,1)\rangle to \mathbb{Z}
\mathbb{Z}\times\mathbb{Z}/\langle (2,2)\rangle
This should also be a finitely generated abelian group. (\mathbb{Z}_2\times \mathbb{Z} actually)
Take \phi(a,b)=(a\mod 2,a-b)
More generally, for \mathbb{Z}\times \mathbb{Z}/\langle (a,b)\rangle.
This should be \mathbb{Z}\times \mathbb{Z}_{\operatorname{gcd}(a,b)}
Try to do section by gcd.
- If
Gis abelian,N\leq G, thenG/Nis abelian.- If
Gis finitely generated andN\trianglelefteq G, thenG/Nis finitely generated.
Definition of simple group
G is simple if G has no proper (H\neq G,\{e\}), normal subgroup.
Tip
In general
S_nis not simple, consider the normal subgroupA_n.
Example of some natural normal subgroups
If \phi:G\to G' is a homomorphism, then \ker(\phi)\trianglelefteq G.
The center of G: Z(G)=\{a\in G|ag=ga\text{ for all }g\in G\}
Z(G)\trianglelefteq G.
e\in Z(G).a,b\in Z(G)\implies abg=gab\implies ab\in Z(G).a\in Z(G)\implies ag=ga\implies a^{-1}\in Z(G).- If
g\in G, h\in Z(G), thenghg^{-1}\in Z(G)sinceghg^{-1}=gg^{-1}h=h.
Z(S_3)=\{e\}, all the transpositions are not commutative, so Z(S_3)=\{e\}.
Z(GL_n(\mathbb{R}))? continue on friday.