14 KiB
Math 4201 Exam 1 Review
Note
This is a review for definitions we covered in the classes. It may serve as a cheat sheet for the exam if you are allowed to use it.
The exam will have 5 problems, roughly covering the following types of questions:
- Define concepts from class (e.g. what is the definition of the interior of a set?)
- Give an example of a space/map which satisfies/does not satisfy a certain property (e.g. give an example of a map that is not continuous.)
- Proofs from the lectures
- Homework problems
- A new problem at the same level of difficulty as homework problems
Topological space
Basic definitions
Definition for topological space
A topological space is a pair of set X and a collection of subsets of X, denoted by \mathcal{T} (imitates the set of "open sets" in X), satisfying the following axioms:
\emptyset \in \mathcal{T}andX \in \mathcal{T}\mathcal{T}is closed with respect to arbitrary unions. This means, for any collection of open sets\{U_\alpha\}_{\alpha \in I}, we have\bigcup_{\alpha \in I} U_\alpha \in \mathcal{T}\mathcal{T}is closed with respect to finite intersections. This means, for any finite collection of open sets\{U_1, U_2, \ldots, U_n\}, we have\bigcap_{i=1}^n U_i \in \mathcal{T}
Definition of open set
U\subseteq X is an open set if U\in \mathcal{T}
Definition of closed set
Z\subseteq X is a closed set if X\setminus Z\in \mathcal{T}
Warning
A set is closed is not the same as its not open.
In all topologies over non-empty sets,
X, \emptysetare both closed and open.
Basis
Definition of topological basis
For a set X, a topology basis, denoted by \mathcal{B}, is a collection of subsets of X, such that the following properties are satisfied:
- For any
x \in X, there exists aB \in \mathcal{B}such thatx \in B(basis covers the whole space) - If
B_1, B_2 \in \mathcal{B}andx \in B_1 \cap B_2, then there exists aB_3 \in \mathcal{B}such thatx \in B_3 \subseteq B_1 \cap B_2(every non-empty intersection of basis elements are also covered by a basis element)
Definition of topology generated by basis
Let \mathcal{B} be a basis for a topology on a set X. Then the topology generated by \mathcal{B} is defined by the set as follows:
\mathcal{T}_{\mathcal{B}} \coloneqq \{ U \subseteq X \mid \forall x\in U, \exists B\in \mathcal{B} \text{ such that } x\in B\subseteq U \}
This is basically a closure of
\mathcal{B}under arbitrary unions and finite intersections
Lemma of topology generated by basis
U\in \mathcal{T}_{\mathcal{B}}\iff \exists \{B_\alpha\}_{\alpha \in I}\subseteq \mathcal{B} such that U=\bigcup_{\alpha \in I} B_\alpha
Definition of basis generated from a topology
Let (X, \mathcal{T}) be a topological space. Then the basis generated from a topology is \mathcal{C}\subseteq \mathcal{B} such that \forall U\in \mathcal{T}, \forall x\in U, \exists B\in \mathcal{C} such that x\in B\subseteq U.
Definition of subbasis of topology
A subbasis of a topology is a collection \mathcal{S}\subseteq \mathcal{T} such that \bigcup_{U\in \mathcal{S}} U=X.
Definition of topology generated by subbasis
Let \mathcal{S}\subseteq \mathcal{T} be a subbasis of a topology on X, then the basis generated by such subbasis is the closure of finite intersection of \mathcal{S}
\mathcal{B}_{\mathcal{S}} \coloneqq \{B\mid B\text{ is the intersection of a finite number of elements of }\mathcal{S}\}
Then the topology generated by \mathcal{B}_{\mathcal{S}} is the subbasis topology denoted by \mathcal{T}_{\mathcal{S}}.
Note that all open set with respect to \mathcal{T}_{\mathcal{S}} can be written as a union of finitely intersections of elements of \mathcal{S}
Comparing topologies
Definition of finer and coarser topology
Let (X,\mathcal{T}) and (X,\mathcal{T}') be topological spaces. Then \mathcal{T} is finer than \mathcal{T}' if \mathcal{T}'\subseteq \mathcal{T}. \mathcal{T} is coarser than \mathcal{T}' if \mathcal{T}\subseteq \mathcal{T}'.
Lemma of comparing basis
Let (X,\mathcal{T}) and (X,\mathcal{T}') be topological spaces with basis \mathcal{B} and \mathcal{B}'. Then \mathcal{T} is finer than \mathcal{T}' if and only if for any x\in X, x\in B', B'\in \mathcal{B}', there exists B\in \mathcal{B}, such that x\in B and x\in B\subseteq B'.
Product space
Definition of cartesian product
Let X,Y be sets. The cartesian product of X and Y is the set of all ordered pairs (x,y) where x\in X and y\in Y, denoted by X\times Y.
Definition of product topology
Let (X,\mathcal{T}_X) and (Y,\mathcal{T}_Y) be topological spaces. Then the product topology on X\times Y is the topology generated by the basis
\mathcal{B}_{X\times Y}=\{U\times V, U\in \mathcal{T}_X, V\in \mathcal{T}_Y\}
or equivalently,
\mathcal{B}_{X\times Y}'=\{U\times V, U\in \mathcal{B}_X, V\in \mathcal{B}_Y\}
Product topology generated from open sets of
XandYis the same as product topology generated from their corresponding basis
Subspace topology
Definition of subspace topology
Let (X,\mathcal{T}) be a topological space and Y\subseteq X. Then the subspace topology on Y is the topology given by
\mathcal{T}_Y=\{U\cap Y|U\in \mathcal{T}\}
or equivalently, let \mathcal{B} be the basis for (X,\mathcal{T}). Then the subspace topology on Y is the topology generated by the basis
\mathcal{B}_Y=\{U\cap Y| U\in \mathcal{B}\}
Lemma of open sets in subspace topology
Let (X,\mathcal{T}) be a topological space and Y\subseteq X. Then if U\subseteq Y, U is open in (Y,\mathcal{T}_Y), then U is open in (X,\mathcal{T}).
This also holds for closed set in closed subspace topology
Interior and closure
Definition of interior
The interior of A is the largest open subset of A.
A^\circ=\bigcup_{U\subseteq A, U\text{ is open in }X} U
Definition of closure
The closure of A is the smallest closed superset of A.
\overline{A}=\bigcap_{U\supseteq A, U\text{ is closed in }X} U
Definition of neighborhood
A neighborhood of a point x\in X is an open set U\in \mathcal{T} such that x\in U.
Definition of limit points
A point x\in X is a limit point of A if every neighborhood of x contains a point in A-\{x\}.
We denote the set of all limits points of A by A'.
\overline{A}=A\cup A'
Sequences and continuous functions
Definition of convergence
Let X be a topological space. A sequence (x_n)_{n\in\mathbb{N}_+} in X converges to x\in X if for any neighborhood U of x, there exists N\in\mathbb{N}_+ such that \forall n\geq N, x_n\in U.
Definition of Hausdoorff space
A topological space (X,\mathcal{T}) is Hausdorff if for any two distinct points x,y\in X, there exist open neighborhoods U and V of x and y respectively such that U\cap V=\emptyset.
Uniqueness of convergence in Hausdorff spaces
In a Hausdorff space, if a sequence (x_n)_{n\in\mathbb{N}_+} converges to x\in X and y\in X, then x=y.
Closed singleton in Hausdorff spaces
In a Hausdorff space, if x\in X, then \{x\} is a closed set.
Definition of continuous function
Let (X,\mathcal{T}_X) and (Y,\mathcal{T}_Y) be topological spaces. A function f:X\to Y is continuous if for any open set U\subseteq Y, f^{-1}(U) is open in X.
Definition of point-wise continuity
Let (X,\mathcal{T}_X) and (Y,\mathcal{T}_Y) be topological spaces. A function f:X\to Y is point-wise continuous at x\in X if for every openset V\subseteq Y, f(x)\in V then there exists an open set U\subseteq X such that x\in U and f(U)\subseteq V.
Lemma of continuous functions
If f:X\to Y is point-wise continuous for all x\in X, then f is continuous.
Properties of continuous functions
If f:X\to Y is continuous, then
\forall A\subseteq Y,f^{-1}(A^c)=X\setminus f^{-1}(A)(complements maps to complements)\forall A_\alpha\subseteq Y, \alpha\in I,f^{-1}(\bigcup_{\alpha\in I} A_\alpha)=\bigcup_{\alpha\in I} f^{-1}(A_\alpha)\forall A_\alpha\subseteq Y, \alpha\in I,f^{-1}(\bigcap_{\alpha\in I} A_\alpha)=\bigcap_{\alpha\in I} f^{-1}(A_\alpha)f^{-1}(U)is open inXfor any open setU\subseteq Y.fis continuous atx\in X.f^{-1}(V)is closed inXfor any closed setV\subseteq Y.- Assume
\mathcal{B}is a basis forY, thenf^{-1}(\mathcal{B})is open inXfor anyB\in \mathcal{B}. \forall A\subseteq X,\overline{f(A)}=f(\overline{A})
Definition of homeomorphism
Let (X,\mathcal{T}_X) and (Y,\mathcal{T}_Y) be topological spaces. A function f:X\to Y is a homeomorphism if f is continuous, bijective and f^{-1}:Y\to X is continuous.
Ways to construct continuous functions
- If
f:X\to Yis constant function,f(x)=y_0for allx\in X, thenfis continuous. (constant functions are continuous) - If
Ais a subspace ofX,f:A\to Xis the inclusion mapf(x)=xfor allx\in A, thenfis continuous. (inclusion maps are continuous) - If
f:X\to Yis continuous,g:Y\to Zis continuous, theng\circ f:X\to Zis continuous. (composition of continuous functions is continuous) - If
f:X\to Yis continuous,Ais a subspace ofX, thenf|_A:X\to Yis continuous. (domain restriction is continuous) - If
f:X\to Yis continuous,Zis a subspace ofY, thenf:X\to Z,g(x)=f(x)\cap Zis continuous. IfYis a subspace ofZ, thenh:X\to Z,h(x)=f(x)is continuous (composition offand inclusion map). - If
f:X\to Yis continuous,Xcan be written as a union of open sets\{U_\alpha\}_{\alpha\in I}, thenf|_{U_\alpha}:X\to Yis continuous. - If
X=Z_1\cup Z_2, andZ_1,Z_2are closed equipped with subspace topology, letg_1:Z_1\to Yandg_2:Z_2\to Ybe continuous, and for allx\in Z_1\cap Z_2,g_1(x)=g_2(x), thenf:X\to Ybyf(x)\begin{cases}g_1(x), & x\in Z_1 \\ g_2(x), & x\in Z_2\end{cases}is continuous. (pasting lemma) f:X\to Yis continuous,g:X\to Zis continuous if and only ifH:X\to Y\times Z, whereY\times Zis equipped with the product topology,H(x)=(f(x),g(x))is continuous. (proved in homework)
Metric spaces
Definition of metric
A metric on X is a function d:X\times X\to \mathbb{R} such that \forall x,y\in X,
d(x,x)=0d(x,y)\geq 0d(x,y)=d(y,x)d(x,y)+d(y,z)\geq d(x,z)
Definition of metric ball
The metric ball B_r^{d}(x) is the set of all points y\in X such that d(x,y)\leq r.
Definition of metric topology
Let X be a metric space with metric d. Then X is equipped with the metric topology generated by the metric balls B_r^{d}(x) for r>0.
Definition of metrizable
A topological space (X,\mathcal{T}) is metrizable if it is the metric topology for some metric d on X.
Hausdorff axiom for metric spaces
Every metric space is Hausdorff (take metric balls B_r(x) and B_r(y), r=\frac{d(x,y)}{2}).
If a topology isn't Hausdorff, then it isn't metrizable.
Prove by triangle inequality and contradiction.
Common metrics in \mathbb{R}^n
Euclidean metric
d(x,y)=\sqrt{\sum_{i=1}^n (x_i-y_i)^2}
Square metric
\rho(x,y)=\max_{i=1}^n |x_i-y_i|
Manhattan metric
m(x,y)=\sum_{i=1}^n |x_i-y_i|
These metrics are equivalent.
Product topology and metric
If (X,d),(Y,d') are metric spaces, then X\times Y is metric space with metric d(x,y)=\max\{d(x_1,y_1),d(x_2,y_2)\}.
Uniform metric
Let \mathbb{R}^\omega be the set of all infinite sequences of real numbers. Then \overline{d(x,y)}=\sup_{i=1}^\omega \min\{1,|x_i-y_i|\}, the uniform metric on \mathbb{R}^\omega is a metric.
Metric space and converging sequences
Let X be a topological space, A\subseteq X, x_n\to x such that x_n\in A. Then x\in \overline{A}.
If X is a metric space, A\subseteq X, x\in \overline{A}, then there exists converging sequence x_n\to x such that x_n\in A.
First countability axiom
A topological space (X,\mathcal{T}) satisfies the first countability axiom if any point x\in X, there is a sequence of open neighborhoods of x, \{V_n\}_{n=1}^\infty such that any open neighborhood U of x contains one of V_n.
Apply the theorem above, we have if (X,\mathcal{T}) satisfies the first countability axiom, then every convergent sequence converges to a point in the closure of the sequence.
Metric defined for functions
Definition for bounded metric space
A metric space (Y,d) is bounded if there is M\in \mathbb{R}^{\geq 0} such that for all y_1,y_2\in Y, d(y_1,y_2)\leq M.
Definition for metric defined for functions
Let X be a topological space and Y be a bounded metric space, then the set of all maps, denoted by \operatorname{Map}(X,Y), f:X\to Y\in \operatorname{Map}(X,Y) is a metric space with metric \rho(f,g)=\sup_{x\in X} d(f(x),g(x)).
Space of continuous map is closed
Let (\operatorname{Map}(X,Y),\rho) be a metric space defined above, then every continuous map is a limit point of some sequence of continuous maps.
Z=\{f\in \operatorname{Map}(X,Y)|f\text{ is continuous}\}
Z is closed in (\operatorname{Map}(X,Y),\rho).
Quotient space
Quotient map
Let X be a topological space and X^* is a set. q:X\to X^* is a surjective map. Then q is a quotient map.
Quotient topology
Let (X,\mathcal{T}) be a topological space and X^* be a set, q:X\to X^* is a surjective map. Then
\mathcal{T}^* \coloneqq \{U\subseteq X^*\mid q^{-1}(U)\in \mathcal{T}\}
is a topology on X^* called quotient topology.
(X^*,\mathcal{T}^*) is called the quotient space of X by q.
Equivalent classes
\sim is a subset of X\times X with the following properties:
x\sim xfor allx\in X.- If
(x,y)\in \sim, then(y,x)\in \sim. - If
(x,y)\in \simand(y,z)\in \sim, then(x,z)\in \sim.
The equivalence classes of x\in X is denoted by [x]=\{y\in X|y\sim x\}.