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Math4202 Topology II (Lecture 10)
Algebraic Topology
Path homotopy
Theorem for properties of product of paths
- If
f\simeq_p f_1, g\simeq_p g_1, thenf*g\simeq_p f_1*g_1. (Product is well-defined) ([f]*[g])*[h]=[f]*([g]*[h]). (Associativity)- Let
e_{x_0}be the constant path fromx_0tox_0,e_{x_1}be the constant path fromx_1tox_1. Supposefis a path fromx_0tox_1.
(Right and left identity)[e_{x_0}]*[f]=[f],\quad [f]*[e_{x_1}]=[f] - Given
finXa path fromx_0tox_1, we define\bar{f}to be the path fromx_1tox_0where\bar{f}(t)=f(1-t).f*\bar{f}=e_{x_0},\quad \bar{f}*f=e_{x_1}[f]*[\bar{f}]=[e_{x_0}],\quad [\bar{f}]*[f]=[e_{x_1}]
Proof
(1) If f\simeq_p f_1, g\simeq_p g_1, then f*g\simeq_p f_1*g_1.
Let F be homotopy between f and f_1, G be homotopy between g and g_1.
We can define
F*G:[0,1]\times [0,1]\to X,\quad F*G(s,t)=\left(F(-,t)*G(-,t)\right)(s)=\begin{cases}
F(2s,t) & 0\leq s\leq \frac{1}{2}\\
G(2s-1,t) & \frac{1}{2}\leq s\leq 1
\end{cases}
F*G is a homotopy between f*g and f_1*g_1.
We can check this by enumerating the cases from definition of homotopy.
(2) ([f]*[g])*[h]=[f]*([g]*[h]).
For f*(g*h), along the interval [0,\frac{1}{2}] we map x_1\to x_2, then along the interval [\frac{1}{2},\frac{3}{4}] we map x_2\to x_3, then along the interval [\frac{3}{4},1] we map x_3\to x_4.
For (f*g)*h, along the interval [0,\frac{1}{4}] we map x_1\to x_2, then along the interval [\frac{1}{4},\frac{1}{2}] we map x_2\to x_3, then along the interval [\frac{1}{2},1] we map x_3\to x_4.
We can construct the homotopy between f*(g*h) and (f*g)*h as follows.
Let f((4-2t)s) for F(s,t),
when t=0, F(s,0)=f(4s)\in f*(g*h), when t=1, F(s,1)=f(2s)\in (f*g)*h.
....
We make the linear maps between f*(g*h) and (f*g)*h continuous, then f*(g*h)\simeq_p (f*g)*h. With our homotopy constructed above
(3) e_{x_0}*f\simeq_p f\simeq_p f*e_{x_1}.
We can construct the homotopy between e_{x_0}*f and f as follows.
H(s,t)=\begin{cases}
x_0 & t\geq 2s\\
f(2s-t) & t\leq 2s
\end{cases}
or you may induct from f(\frac{s-t/2}{1-t/2}) if you like.
(4) f*\bar{f}=e_{x_0},\quad \bar{f}*f=e_{x_1}.
Note that we don't need to reach x_1 every time.
f_t=f(ts) s\in[0,\frac{1}{2}].
\bar{f}_t=\bar{f}(1-ts) s\in[\frac{1}{2},1].
Caution
Homeomorphism does not implies homotopy automatically.
Definition for the fundamental group
The fundamental group of X at x is defined to be
(\Pi_1(X,x),*)