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# Math 416 Midterm 1 Review
So everything we have learned so far is to extend the real line to the complex plane.
## Chapter 0 Calculus on Real values
### Differentiation
Let $f,g$ be function on real line and $c$ be a real number.
$$
\frac{d}{dx}(f+g)=f'+g'
$$
$$
\frac{d}{dx}(cf)=cf'
$$
$$
\frac{d}{dx}(fg)=f'g+fg'
$$
$$
\frac{d}{dx}(f/g)=(f'g-fg')/g^2
$$
$$
\frac{d}{dx}(f\circ g)=(f'\circ g)\frac{d}{dx}g
$$
$$
\frac{d}{dx}x^n=nx^{n-1}
$$
$$
\frac{d}{dx}e^x=e^x
$$
$$
\frac{d}{dx}\ln x=\frac{1}{x}
$$
$$
\frac{d}{dx}\sin x=\cos x
$$
$$
\frac{d}{dx}\cos x=-\sin x
$$
$$
\frac{d}{dx}\tan x=\sec^2 x
$$
$$
\frac{d}{dx}\sec x=\sec x\tan x
$$
$$
\frac{d}{dx}\csc x=-\csc x\cot x
$$
$$
\frac{d}{dx}\sinh x=\cosh x
$$
$$
\frac{d}{dx}\cosh x=\sinh x
$$
$$
\frac{d}{dx}\tanh x=\operatorname{sech}^2 x
$$
$$
\frac{d}{dx}\operatorname{sech} x=-\operatorname{sech}x\tanh x
$$
$$
\frac{d}{dx}\operatorname{csch} x=-\operatorname{csch}x\coth x
$$
$$
\frac{d}{dx}\coth x=-\operatorname{csch}^2 x
$$
$$
\frac{d}{dx}\arcsin x=\frac{1}{\sqrt{1-x^2}}
$$
$$
\frac{d}{dx}\arccos x=-\frac{1}{\sqrt{1-x^2}}
$$
$$
\frac{d}{dx}\arctan x=\frac{1}{1+x^2}
$$
$$
\frac{d}{dx}\operatorname{arccot} x=-\frac{1}{1+x^2}
$$
$$
\frac{d}{dx}\operatorname{arcsec} x=\frac{1}{x\sqrt{x^2-1}}
$$
$$
\frac{d}{dx}\operatorname{arccsc} x=-\frac{1}{x\sqrt{x^2-1}}
$$
### Integration
Let $f,g$ be function on real line and $c$ be a real number.
$$
\int (f+g)dx=\int fdx+\int gdx
$$
$$
\int cfdx=c\int fdx
$$
$$
\int e^x dx=e^x
$$
$$
\int \ln x dx=x\ln x-x
$$
$$
\int \frac{1}{x} dx=\ln|x|
$$
$$
\int \sin x dx=-\cos x
$$
$$
\int \cos x dx=\sin x
$$
$$
\int \tan x dx=-\ln|\cos x|
$$
$$
\int \cot x dx=\ln|\sin x|
$$
$$
\int \sec x dx=\ln|\sec x+\tan x|
$$
$$
\int \csc x dx=\ln|\csc x-\cot x|
$$
$$
\int \sinh x dx=\cosh x
$$
$$
\int \cosh x dx=\sinh x
$$
$$
\int \tanh x dx=\ln|\cosh x|
$$
$$
\int \coth x dx=\ln|\sinh x|
$$
$$
\int \operatorname{sech} x dx=2\arctan(\tanh(x/2))
$$
$$
\int \operatorname{csch} x dx=\ln|\coth x-\operatorname{csch} x|
$$
$$
\int \operatorname{sech}^2 x dx=\tanh x
$$
$$
\int \operatorname{csch}^2 x dx=-\coth x
$$
$$
\int \frac{1}{1+x^2} dx=\arctan x
$$
$$
\int \frac{1}{x^2+1} dx=\arctan x
$$
$$
\int \frac{1}{x^2-1} dx=\frac{1}{2}\ln|\frac{x-1}{x+1}|
$$
$$
\int \frac{1}{x^2-a^2} dx=\frac{1}{2a}\ln|\frac{x-a}{x+a}|
$$
$$
\int \frac{1}{x^2+a^2} dx=\frac{1}{a}\arctan(\frac{x}{a})
$$
$$
\int \frac{1}{\sqrt{x^2-a^2}} dx=\ln|x+\sqrt{x^2-a^2}|
$$
$$
\int \frac{1}{\sqrt{x^2+a^2}} dx=\ln|x+\sqrt{x^2+a^2}|
$$
## Chapter 1 Complex Numbers
### Definition of complex numbers
An ordered pair of real numbers $(x, y)$ can be represented as a complex number $z = x + yi$, where $i$ is the imaginary unit.
With operations defined as:
$$
(x_1 + y_1i) + (x_2 + y_2i) = (x_1 + x_2) + (y_1 + y_2)i
$$
$$
(x_1 + y_1i) \cdot (x_2 + y_2i) = (x_1x_2 - y_1y_2) + (x_1y_2 + x_2y_1)i
$$
#### Modulus
The modulus of a complex number $z = x + yi$ is defined as
$$
|z| = \sqrt{x^2 + y^2}=|z\overline{z}|
$$
### De Moivre's Formula
Every complex number $z$ can be written as $z = r(\cos \theta + i \sin \theta)$, where $r$ is the magnitude of $z$ and $\theta$ is the argument of $z$.
$$
z^n = r^n(\cos n\theta + i \sin n\theta)
$$
The De Moivre's formula is useful for finding the $n$th roots of a complex number.
$$
z^n = r^n(\cos n\theta + i \sin n\theta)
$$
### Roots of complex numbers
Using De Moivre's formula, we can find the $n$th roots of a complex number.
If $z=r(\cos \theta + i \sin \theta)$, then the $n$th roots of $z$ are given by:
$$
z_k = r^{1/n}(\cos \frac{\theta + 2k\pi}{n} + i \sin \frac{\theta + 2k\pi}{n})
$$
for $k = 0, 1, 2, \ldots, n-1$.
### Stereographic projection
![Stereographic projection](https://notenextra.trance-0.com/Math416/Stereographic_projection.png)
The stereographic projection is a map from the unit sphere $S^2$ to the complex plane $\mathbb{C}\setminus\{0\}$.
The projection is given by:
$$
z\mapsto \frac{(2Re(z), 2Im(z), |z|^2-1)}{|z|^2+1}
$$
The inverse map is given by:
$$
(\xi,\eta, \zeta)\mapsto \frac{\xi + i\eta}{1 - \zeta}
$$
## Chapter 2 Complex Differentiation
### Definition of complex differentiation
Let the complex plane $\mathbb{C}$ be defined in an open subset $G$ of $\mathbb{C}$. (Domain)
Then $f$ is said to be differentiable at $z_0\in G$ if the limit
$$
\lim_{z\to z_0} \frac{f(z)-f(z_0)}{z-z_0}
$$
exists.
The limit is called the derivative of $f$ at $z_0$ and is denoted by $f'(z_0)$.
To prove that a function is differentiable, we can use the standard delta-epsilon definition of a limit.
$$
\left|\frac{f(z)-f(z_0)}{z-z_0} - f'(z_0)\right| < \epsilon
$$
whenever $0 < |z-z_0| < \delta$.
With such definition, all the properties of real differentiation can be extended to complex differentiation.
#### Differentiation of complex functions
1. If $f$ is differentiable at $z_0$, then $f$ is continuous at $z_0$.
2. If $f,g$ are differentiable at $z_0$, then $f+g, fg$ are differentiable at $z_0$.
$$
(f+g)'(z_0) = f'(z_0) + g'(z_0)
$$
$$
(fg)'(z_0) = f'(z_0)g(z_0) + f(z_0)g'(z_0)
$$
3. If $f,g$ are differentiable at $z_0$ and $g(z_0)\neq 0$, then $f/g$ is differentiable at $z_0$.
$$
\left(\frac{f}{g}\right)'(z_0) = \frac{f'(z_0)g(z_0) - f(z_0)g'(z_0)}{g(z_0)^2}
$$
4. If $f$ is differentiable at $z_0$ and $g$ is differentiable at $f(z_0)$, then $g\circ f$ is differentiable at $z_0$.
$$
(g\circ f)'(z_0) = g'(f(z_0))f'(z_0)
$$
5. If $f(z)=\sum_{k=0}^n c_k(z-z_0)^k$, where $c_k\in\mathbb{C}$, then $f$ is differentiable at $z_0$ and $f'(z_0)=\sum_{k=1}^n kc_k(z_0-z_0)^{k-1}$.
$$
f'(z_0) = c_1 + 2c_2(z_0-z_0) + 3c_3(z_0-z_0)^2 + \cdots + nc_n(z_0-z_0)^{n-1}
$$
### Cauchy-Riemann Equations
Let the function defined on an open subset $G$ of $\mathbb{C}$ be $f(x,y)=u(x,y)+iv(x,y)$, where $u,v$ are real-valued functions.
Then $f$ is differentiable at $z_0=x_0+y_0i$ if and only if the partial derivatives of $u$ and $v$ exist at $(x_0,y_0)$ and satisfy the Cauchy-Riemann equations:
$$
\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y}, \quad \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}
$$
On the polar form, the Cauchy-Riemann equations are
$$
r\frac{\partial u}{\partial r} = \frac{\partial v}{\partial \theta}, \quad \frac{\partial u}{\partial \theta} = -r\frac{\partial v}{\partial r}
$$
### Holomorphic functions
A function $f$ is said to be holomorphic on an open subset $G$ of $\mathbb{C}$ if $f$ is differentiable at every point of $G$.
#### Partial differential operators
$$
\frac{\partial}{\partial z} = \frac{1}{2}\left(\frac{\partial}{\partial x} - i\frac{\partial}{\partial y}\right)
$$
$$
\frac{\partial}{\partial \bar{z}} = \frac{1}{2}\left(\frac{\partial}{\partial x} + i\frac{\partial}{\partial y}\right)
$$
This gives that
$$
\frac{\partial f}{\partial z} = \frac{1}{2}\left(\frac{\partial f}{\partial x} - i\frac{\partial f}{\partial y}\right)=\frac{1}{2}\left(\frac{\partial u}{\partial x} +\frac{\partial v}{\partial y}\right) + \frac{i}{2}\left(\frac{\partial v}{\partial x} - \frac{\partial u}{\partial y}\right)
$$
$$
\frac{\partial f}{\partial \bar{z}} = \frac{1}{2}\left(\frac{\partial f}{\partial x} + i\frac{\partial f}{\partial y}\right)=\frac{1}{2}\left(\frac{\partial u}{\partial x} - \frac{\partial v}{\partial y}\right) + \frac{i}{2}\left(\frac{\partial u}{\partial y} + \frac{\partial v}{\partial x}\right)
$$
If the function $f$ is holomorphic, then by the Cauchy-Riemann equations, we have
$$
\frac{\partial f}{\partial \bar{z}} = 0
$$
### Conformal mappings
A holomorphic function $f$ is said to be conformal if it preserves the angles between the curves. More formally, if $f$ is holomorphic on an open subset $G$ of $\mathbb{C}$ and $z_0\in G$, $\gamma_1, \gamma_2$ are two curves passing through $z_0$ ($\gamma_1(t_1)=\gamma_2(t_2)=z_0$) and intersecting at an angle $\theta$, then
$$
\arg(f\circ\gamma_1)'(t_1) - \arg(f\circ\gamma_2)'(t_2) = \theta
$$
In other words, the angle between the curves is preserved.
An immediate consequence is that
$$
\arg(f\cdot \gamma_1)'(t_1) =\arg f'(z_0) + \arg \gamma_1'(t_1)\\
\arg(f\cdot \gamma_2)'(t_2) =\arg f'(z_0) + \arg \gamma_2'(t_2)
$$
### Harmonic functions
A real-valued function $u$ is said to be harmonic if it satisfies the Laplace equation:
$$
\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0
$$
## Chapter 3 Linear Fractional Transformations
### Definition of linear fractional transformations
A linear fractional transformation is a function of the form
$$
\phi(z) = \frac{az+b}{cz+d}
$$
where $a,b,c,d$ are complex numbers and $ad-bc\neq 0$.
### Properties of linear fractional transformations
#### Matrix form
A linear fractional transformation can be written as a matrix multiplication:
$$
\phi(z) = \begin{bmatrix}
a & b\\
c & d\\
\end{bmatrix}
\begin{bmatrix}
z\\
1\\
\end{bmatrix}
$$
#### Conformality
A linear fractional transformation is conformal.
$$
\phi'(z) = \frac{ad-bc}{(cz+d)^2}
$$
#### Three-fold transitivity
If $z_1,z_2,z_3$ are distinct points in the complex plane, then there exists a unique linear fractional transformation $\phi$ such that $\phi(z_1)=\infty$, $\phi(z_2)=0$, $\phi(z_3)=1$.
The map is given by
$$
\phi(z) =\begin{cases}
\frac{(z-z_2)(z_1-z_3)}{(z-z_1)(z_2-z_3)} & \text{if } z_1,z_2,z_3 \text{ are all finite}\\
\frac{z-z_2}{z_3-z_2} & \text{if } z_1=\infty\\
\frac{z_3-z_1}{z-z_1} & \text{if } z_2=\infty\\
\frac{z-z_2}{z-z_1} & \text{if } z_3=\infty\\
\end{cases}
$$
So if $z_1,z_2,z_3$, $w_1,w_2,w_3$ are distinct points in the complex plane, then there exists a unique linear fractional transformation $\phi$ such that $\phi(z_i)=w_i$ for $i=1,2,3$.
#### Factorization
Every linear fractional transformation can be written as a composition of homothetic mappings, translations, inversions, and multiplications.
If $\phi(z)=\frac{az+b}{cz+d}$, then
$$
\phi(z) = \frac{b-ad/c}{cz+d}+\frac{a}{c}
$$
#### Clircle
A linear-fractional transformation maps circles and lines to circles and lines.
## Chapter 4 Elementary Functions
### Exponential function
The exponential function is defined as
$$
e^z = \sum_{n=0}^\infty \frac{z^n}{n!}
$$
Let $z=x+iy$, then
$$
\begin{aligned}
e^z &= e^{x+iy}\\
&= e^x e^{iy}\\
&= e^x\sum_{n=0}^\infty \frac{(iy)^n}{n!}\\
&= e^x\sum_{n=0}^\infty \frac{(-1)^n y^{2n}}{(2n)!} + i \sum_{n=0}^\infty \frac{(-1)^n y^{2n+1}}{(2n+1)!}\\
&= e^x(\cos y + i\sin y)\\
\end{aligned}
$$
So we can rewrite the polar form of a complex number as
$$
z = r(\cos \theta + i\sin \theta) = re^{i\theta}
$$
#### $e^x$ is holomorphic
Let $f(z)=e^z$, then $u(x,y)=e^x\cos y$, $v(x,y)=e^x\sin y$.
$$
\frac{\partial u}{\partial x} = e^x\cos y = \frac{\partial v}{\partial y}\\
\frac{\partial u}{\partial y} = -e^x\sin y = -\frac{\partial v}{\partial x}
$$
### Trigonometric functions
$$
\sin z = \frac{e^{iz}-e^{-iz}}{2i}, \quad \cos z = \frac{e^{iz}+e^{-iz}}{2}, \quad \tan z = \frac{\sin z}{\cos z}
$$
$$
\sec z = \frac{1}{\cos z}, \quad \csc z = \frac{1}{\sin z}, \quad \cot z = \frac{1}{\tan z}
$$
#### Hyperbolic functions
$$
\sinh z = \frac{e^z-e^{-z}}{2}, \quad \cosh z = \frac{e^z+e^{-z}}{2}, \quad \tanh z = \frac{\sinh z}{\cosh z}
$$
$$
\operatorname{sech} z = \frac{1}{\cosh z}, \quad \operatorname{csch} z = \frac{1}{\sinh z}, \quad \operatorname{coth} z = \frac{1}{\tanh z}
$$
### Logarithmic function
The logarithmic function is defined as
$$
\ln z=\{w\in\mathbb{C}: e^w=z\}
$$
#### Properties of the logarithmic function
Let $z=x+iy$, then
$$
|e^z|=\sqrt{e^x(\cos y)^2+(\sin y)^2}=e^x
$$
So we have
$$
\log z = \ln |z| + i\arg z
$$
### Power function
### Inverse trigonometric functions
## Chapter 5 Power Series
### Definition of power series
A power series is a series of the form
$$
\sum_{n=0}^\infty a_n (z-z_0)^n
$$
### Properties of power series
#### Geometric series
$$
\sum_{n=0}^\infty z^n = \frac{1}{1-z}, \quad |z|<1
$$
### Radius/Region of convergence
### Cauchy-Hadamard Theorem
### Cauchy Product (of power series)
## Chapter 6 Complex Integration
### Definition of Riemann Integral for complex functions
The complex integral of a complex function $\phi$ on the closed subinterval $[a,b]$ of the real line is said to be piecewise continuous if there exists a partition $a=t_0<t_1<\cdots<t_n=b$ such that $\phi$ is continuous on each open interval $(t_{i-1},t_i)$ and has a finite limit at each discontinuity point of the closed interval $[a,b]$.
If $\phi$ is piecewise continuous on $[a,b]$, then the complex integral of $\phi$ on $[a,b]$ is defined as
$$
\int_a^b \phi(t) dt = \int_a^b \operatorname{Re}\phi(t) dt + i\int_a^b \operatorname{Im}\phi(t) dt
$$
### Fundamental Theorem of Calculus
If $\phi$ is piecewise continuous on $[a,b]$, then
$$
\int_a^b \phi'(t) dt = \phi(b)-\phi(a)
$$
### Triangle inequality
$$
\left|\int_a^b \phi(t) dt\right| \leq \int_a^b |\phi(t)| dt
$$
### Integral on curve
Let $\gamma$ be a piecewise smooth curve in the complex plane.
The integral of a complex function $f$ on $\gamma$ is defined as
$$
\int_\gamma f(z) dz = \int_a^b f(\gamma(t))\gamma'(t) dt
$$
### Properties of complex integrals
1. Linearity:
## Chapter 7 Cauchy's Theorem
### Cauchy's Theorem
### Cauchy's Formula for a Circle
### Cauchy's Product