procedural updating

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Trance-0
2025-02-11 11:16:11 -06:00
parent 0b1ea591c1
commit 05e62532da
2 changed files with 56 additions and 15 deletions

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@@ -58,8 +58,7 @@ $$
>
> A function $g(h)$ is $o(h)$ if $\lim_{h\to 0}\frac{g(h)}{h}=0$.
>
> <!---TODO: check after lecture-->
> $f$ is differentiable if and only if $f(z+h)=f(z)+f'(z)h+\frac{1}{2}h^2f''(z)+o(h^3)$ as $h\to 0$.
> $f$ is differentiable if and only if $f(z+h)=f(z)+f'(z)h+\frac{1}{2}h^2f''(z)+o(h^3)$ as $h\to 0$. (By Taylor expansion)
Since $f$ is holomorphic at $\gamma(t_0)=\zeta_0$, we have
@@ -88,13 +87,13 @@ $$
EOP
#### Definition of conformal function
#### Definition 2.12 (Conformal function)
A function $f:G\to \mathbb{C}$ is called conformal if it preserves the angle between two curves.
#### Theorem of conformal function
#### Theorem 2.13 (Conformal function)
If $f:G\to \mathbb{C}$ is holomorphic function on open set $G\subset \mathbb{C}$ and $\gamma_1,\gamma_2$ are regular curves in $G$ with $\gamma_1(t_0)=\gamma_2(t_0)=\zeta_0$ for some $t_0\in I_1\cap I_2$, and $f'(\zeta_0)\neq 0$, then $f$ is conformal at $\zeta_0$.
If $f:G\to \mathbb{C}$ is conformal at $\zeta_0\in G$, then $f$ is holomorphic at $\zeta_0$ and $f'(\zeta_0)\neq 0$.
Example:
@@ -104,8 +103,6 @@ $$
is not conformal at $z=0$ because $f'(0)=0$.
#### Lemma of conformal function
Suppose $f$ is real differentiable, let $a=\frac{\partial f}{\partial \zeta}(\zeta_0)$, $b=\frac{\partial f}{\partial \overline{\zeta}}(\zeta_0)$.