This commit is contained in:
Zheyuan Wu
2025-02-26 10:51:23 -06:00
parent abc85a9375
commit ae52024b7b
4 changed files with 75 additions and 6 deletions

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@@ -3,7 +3,7 @@ services:
build:
context: ./
dockerfile: ./Dockerfile
image: trance0/notenextra:v1.1.1
image: trance0/notenextra:v1.1.2
restart: on-failure:5
ports:
- 13000:3000

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@@ -54,7 +54,7 @@ What is the structure of $S=[0,1]\setminus T$? (or Sparse)
- Topologically (not dense)
- Measure, for now meaning small or zero outer content.
## Chapter 4: Nowhere Dense SEts and the Problem with the Fundamental Theorem of Calculus
## Chapter 4: Nowhere Dense Sets and the Problem with the Fundamental Theorem of Calculus
### Nowhere Dense Sets

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@@ -1 +1,72 @@
# Lecture 18
# Math4121 Lecture 18
## Continue
### Small sets
A set that is nowhere dense, has zero outer content yet is uncountable.
By modifying this example, we can find similar with any outer content between 0 and 1.
#### Definition: Perfect Set
$S\subsetes[0,1]$ is perfect if $S=S'$.
Example:
- $[0,1]$ is perfect
- perfect sets are closed
- Finite collection of points is not perfect because they do not have limit points.
- perfect sets are uncountable (no countable sets can be perfect)
#### Middle third Cantor set
We construct the set by removing the middle third of the interval.
Let $C_0=[0,1]$, $C_1=[0,\frac{1}{3}]\cup[\frac{2}{3}]$ ...
Continuing this process indefinitely, we define the Cantor set as
$$
C=\Bigcap_{n=0}^{\infty}C_n
$$
1. $C_n\subseteq C_{n-1}$
2. $\ell(C_n)=\ell(C_{n-1})$
3. Each $C_n$ is closed.
> The algebraic expression for $C_n$, where $a\in[0,1]$, we write as a decimal expansion in base $3$.
>
> $$ a=\sum_{n=1}^{\infty} \frac{a_n}{3^n}$$, where $a_n\in\{0,1,2\}$.
>
> In this case, $C_0\to C_1$ means deleting all numbers with $a_1=1$. (the same as deleting the interval $[\frac{1}{3},\frac{2}{3}]$)
>
> $C_1\to C_2$ means deleting all the numbers with $a_2=1$.$
>
> So we can write the set as $$C=\left\{\sum_{n=1}^{\infty}\frac{a_n}{3^n},a_n\in\{0,2\}\right\}$$
#### Proposition 4.1
$C$ is perfect and nowhere dense, and outer content is 0.
Proof:
(i) $c_e(C)=0$
Let $\epsilon>0$, then $\exists n$ such that $\left(\frac{2}{3}\right)<\epsilon$. Then $C_n$ is a cover of $C$, and $\ell(C_n)<\epsilon$.
(ii) $C$ is perfect
Since $C_n$ is closed, $C$ is closed (any intersection of closed set is closed) so $C'\subseteq C$.
Let $a\in C$, and we need to show $a$ is a limit point. Let $\epsilon>0$, and we need to find $a^*\in C\setminus\{a\}$ and $|a^* - a| < \epsilon$. Suppose $a=\sum_{n=1}^{\infty} \frac{a_n}{3^n}, a_n \in \{0, 2\}$, Notive that if $a^*\in C$ has the expansion as $a$ except the k-th term.
So $|a^*-a|=\frac{2}{3^k}$, which can be made arbitrarily small by choosing a sufficiently large $k$. Thus, $a$ is a limit point of $C$, proving that $C$ is perfect.
(iii) $C$ is nowhere dense
It is sufficient to show $C$ contains no intervals.
Any open intervals has a real number with 1 in it's base 3 decimal expansion (proof in homework)
_take some interval in $(a,b)$ we can change the digits that is small enough and keep the element still in the set_

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@@ -20,9 +20,7 @@ export default {
Math4121_L15: "Introduction to Lebesgue Integration (Lecture 15)",
Math4121_L16: "Introduction to Lebesgue Integration (Lecture 16)",
Math4121_L17: "Introduction to Lebesgue Integration (Lecture 17)",
Math4121_L18: {
display: 'hidden'
},
Math4121_L18: "Introduction to Lebesgue Integration (Lecture 18)",
Math4121_L19: {
display: 'hidden'
},