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# Lecture 8
## Chapter III Linear maps
**Assumption: $U,V,W$ are vector spaces (over $\mathbb{F}$)**
### Vector Space of Linear Maps 3A
#### Definition 3.1
A **linear map** from $V$ to $W$ is a function from $T:V\to W$ with the following properties:
1. Additivity: $T(u+v)=T(u)+T(v),\forall u,v\in V$
2. Homogeneity: $T(\lambda v)=\lambda T(v),\forall \lambda \in \mathbb{F},v\in V$
#### Notation
* $Tv=T(v)$
* $\mathscr{L}(V,W)$ denotes the set of linear maps from $V$ to $W$. (homomorphism, $Hom(V,W)$)
* $\mathscr{L}(V)$ denotes the set of linear maps from $V$ to $V$. (endomorphism, $End(V)$)
#### Example
* zero map $0(v)\in \mathscr{L}(V,W)$ $0(v)=0$
* identity map $I\in \mathscr{L}(V,W)$, $I(v)=v$
* scaling map $T\in \mathscr{L}(V,W)$, $T(v)=av,a\in \mathbb{F}$
* differentiation map $D\in \mathscr{L}(\mathscr{P}_m(\mathbb{F}),\mathscr{P}_{m-1}(\mathbb{F}))$, $D(f)=f'$
#### Lemma 3.10
$T0=0$ for $T\in \mathscr{L}(V,W)$
Proof:
$T(0+0)=T(0)+T(0)$
#### Theorem 3.4 Linear map lemma
Suppose $v_1,...,v_n$ is a basis for $V$, and suppose $w_1,...,w_n\in W$ are arbitrary vector. Then, there exists a unique linear map. $T:V\to W$ such that $T_{v_i}=w_i$ for $i=1,...,n$
Proof:
First we show existence.
by constrains,
$T(c_1 v_1,...+c_n v_n)=c_1w_1+...+c_n w_n$
T is well defined because $v_1,....v_n$ are a basis.
Need to show that $T$ is a linear map.
* Additivity: let $u,v\in V$ and suppose $a_1,...,a_n,b_1,...,b_n\in \mathbb{F}$
with $u=a_1v_1+....+a_n v_n ,v=b_1v_1+...+b_2v_n$, then $T(u+v)=T((a_1+b_1)v_1+...+(a_n+b_n)v_n)=Tu+Tv$
Proof for homogeneity used for exercise.
Need to show $T$ is unique. Let $S\in\mathscr{L}(V,W)$ such that $Sv_i=w_i,i=1,...,n$
$$
S(c_1 v_1+...+c_n v_n)=S(c_1v_1)+S(...)+S(c_n v_n)=c_1S(v_1)+...+c_nS(v_n)
+c_1w_1+...+c_nw_n
$$
Then $S=T$
#### Definition 3.5
Let $S,T\in \mathscr{L}(V,W)$, then define
* $(S+T)\in\mathscr{L}(V,W)$ by $(S+T)(v)=Sv+Tv$
* for $\lambda \in \mathbb{F}$, $(\lambda T)\in \mathscr{L}(V,W)$, $(\lambda T)(v)=\lambda T(v)$
Exercises: Show that $S+T$ and $\lambda T$ are linear maps.
#### Theorem 3.6
$\mathscr{L}(V,W)$ is a vector space.
Sketch of proof:
* additive identity: $0(v)=0$
* associativity:
* commutativity:
* additive inverse: $T\to (-1)T=-T$
* scalar multiplication $1T=T$
* distributive
#### Definition 3.7
Multiplication for linear map: $(ST)v=S(T(v))=(S\circ T)(v)$ **Not commutative but associative**.