This commit is contained in:
Zheyuan Wu
2025-03-24 10:54:32 -05:00
parent da7b8f58a6
commit 6805462262
3 changed files with 95 additions and 5 deletions

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build:
context: ./
dockerfile: ./Dockerfile
image: trance0/notenextra:v1.1.8
image: trance0/notenextra:v1.1.9
restart: on-failure:5
ports:
- 13000:3000

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## Continue on Measure Theory
### Borel Mesure
### Borel Measure
Finite additivity of Jordan content, i.e. for any $\{S_j\}_{j=1}^N$ pairwise disjoint sets and Jordan measurable, then
@@ -73,5 +73,3 @@ SVC(3) is Jordan measurable, but $|SVC(3)|=\mathfrak{c}$. so $|\mathscr{P}(SVC(3
But for any $S\subset \mathscr{P}(SVC(3))$, $c_e(S)\leq c_e(SVC(3))=0$ so $S$ is Jordan measurable.
However, there are $\mathfrak{c}$ many intervals and $\mathcal{B}$ is generated by countable operations from intervals.

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# Lecture 26
# Math4121 Lecture 26
## Lebesgue Measure
### Lebesgue's Integration
Partition on the y-axis, let $l$ be the minimum of $f(x)$ on the $y$-axis, $L$ be the maximum of $f(x)$ on the $y$-axis.
$l=l_0<l_1<\cdots<l_n=L$
Define $S_i=\{x\in[a,b]:l_{i-1}\leq f(x)<l_i\}$
Defined the characteristic function of set $S$ is $\chi_S(x)=1$ if $x\in S$ and $0$ otherwise.
Then $f$ lies between the following simple functions:
$$
\sum_{i=1}^n l_{i-1}\chi_{S_i}\leq f(x)\leq \sum_{i=1}^n l_i\chi_{S_i}
$$
_This representation allows us to measure some weird sets on the $x$-axis by constraining the $y$-axis._
This is still kind of Riemann sum, but $S_i$ can be very weird (not just intervals).
If we can "measure" each $S_i$, then we could define the integral of $f$ by
$$
\sup_{l_0,\cdots,l_n}\sum_{i=1}^n l_{i-1}m(S_i)\quad \inf_{l_0,\cdots,l_n}\sum_{i=1}^n l_i m(S_i)
$$
If we used Jordan content, for $m$ here, this is just a different perspective of Riemann integral.
If we use Borel measure maybe things would be different (perhaps, better)?
As we discussed last time, this limits the measurable sets significantly.
Nonetheless, let's try
1. Characteristic function of the rational numbers
$$
f(x)=\begin{cases}
1 & x\in\mathbb{Q}\cap[0,1]\\
0 & \text{otherwise}
\end{cases}
$$
Take partition $0=x_0<x_1<\cdots<x_n=1$
$S_1=\{x:0\leq f(x)<\epsilon\}=[0,1]\setminus\mathbb{Q}$
$S_2=\{x:\epsilon\leq f(x)<1\}=\emptyset$
$S_3=\{x:1\leq f(x)<1+\epsilon\}=\mathbb{Q}\cap[0,1]$
$$
\sum_{i=1}^n l_{i-1}m(S_i)=0\cdot 1+\epsilon\cdot 0+1\cdot 0=0
$$
$$
\sum_{i=1}^n l_i m(S_i)=\epsilon\cdot 1+1\cdot 0+(1+\epsilon)\cdot 0=\epsilon
$$
So, $0\leq\int_0^1 f(x)dm\leq\epsilon$, here $m$ means the measure we used.
As $\epsilon$ is arbitrary, we have $\int_0^1 f(x)dm=0$.
_This shows that $\int \chi_S(x)dm=m(S)$ for any measurable set $S$._
### Lebesgue's Measure
#### Definition of Lebesgue measure
Outer Measure:
Given $S\subset [a,b]$, let $\mathcal{C}$ be the collection of all countable covers of $S$ by open intervals.
$$
m_e(S)=\inf_{C\in\mathcal{C}}m(C)
$$
where $m(C)$ is the Borel measure.
Recall such $C$ are Boreal measurable because open interval are in $\mathcal{B}$ and $\mathcal{B}$ (being a sigma algebra) is closed under countable unions.
Properties:
1. Translation invariant: $m_e(S+a)=m_e(S)$
2. Countable additivity: $m_e(S\cup T)=m_e(S)+m_e(T)$ if $S\cap T=\emptyset$
3. $m([0,1])=1$
**Notice we don't have the difference property here.**